[백준] 16935번 배열 돌리기 3 - 파이썬(Python)

 

문제링크: https://www.acmicpc.net/problem/16935

16935번: 배열 돌리기 3

    import sys
    input = sys.stdin.readline

    n, m, r = map(int,input().split())

    table = []
    temp = []
    for i in range(n):
        table.append(list(map(int,input().split())))

    def one():
        temp = [[0] * m for _ in range(n)]
        for i in range(n):
            temp[i] = (table[n-i-1])

        return temp
    def two():
        temp = [[0] * m for _ in range(n)]
        for i in range(n):
            for j in range(m):
                temp[i][j] = table[i][m-1-j]
        return temp
    def three():
        temp = [[0] * n for _ in range(m)]
        for i in range(m):
            for j in range(n):
                temp[i][j] = table[n-1-j][i]
        return temp
    def four():
        temp = [[0] * n for _ in range(m)]
        for i in range(m):
            for j in range(n):
                temp[i][j] = table[j][m-1-i]
        return temp
    def five():
        temp = [[0] * m for _ in range(n)]
        for i in range(n//2):                   # 4를 1로
            for j in range(m//2):
                temp[i][j] = table[i+n//2][j]

        for i in range(n//2, n):                # 3을 4로
            for j in range(m//2):
                temp[i][j] = table[i][j+m//2]

        for i in range(n//2, n):                # 2를 3으로
            for j in range(m//2, m):
                temp[i][j] = table[i - n//2][j]

        for i in range(n//2):                   # 1을 2로
            for j in range(m//2, m):
                temp[i][j] = table[i][j-m//2]

        return temp
    def six():
        temp = [[0] * m for _ in range(n)]
        for i in range(n//2):                   # 2를 1로
            for j in range(m//2):
                temp[i][j] = table[i][j-m//2]

        for i in range(n//2, n):                # 1을 4로
            for j in range(m//2):
                temp[i][j] = table[i-n//2][j]

        for i in range(n//2, n):                # 4를 3으로
            for j in range(m//2, m):
                temp[i][j] = table[i][j - m//2]

        for i in range(n//2):                   # 3을 2로
            for j in range(m//2, m):
                temp[i][j] = table[i-n//2][j]

        return temp

    for _ in range(r):
        x = list(map(int,input().split()))
        for i in x:
            if i == 1:
                table = one()
            if i == 2:
                table = two()
            if i == 3:
                table = three()
                n,m = m,n
            if i == 4:
                table = four()
                n,m = m,n
            if i == 5:
                table = five()
            if i == 6:
                table = six()

    for i in table:
        print(*i)